Which of the following will form only one oxime on reaction with `NH_(2)OH` solution ?1

Options

A.
B.
C.
D.

Answer

To determine which compound will form only one oxime upon reaction with hydroxylamine (NH2OH), we need to analyze the structure of the compounds involved. Oximes are formed when aldehydes or ketones react with hydroxylamine, resulting in the formation of a C=N-OH bond.

### Step-by-Step Solution:

1. **Identify the Functional Groups**:
- Aldehydes have the general structure RCHO, while ketones have the structure R1R2C=O, where R1 and R2 can be the same or different.

2. **Understand Oxime Formation**:
- Aldehydes and ketones react with hydroxylamine to form oximes. The reaction involves the nucleophilic attack of the nitrogen in hydroxylamine on the carbonyl carbon (C=O), followed by the elimination of water.

3. **Consider Isomer Formation**:
- Aldehydes typically yield only one oxime because they have only one carbon chain attached to the carbonyl carbon.
- Ketones, on the other hand, can yield two different oximes if the two R groups (R1 and R2) attached to the carbonyl carbon are different, leading to the possibility of geometric isomers.

4. **Analyze the Given Options**:
- If the compound is an aldehyde, it will form only one oxime.
- If the compound is a ketone with two different R groups, it can form two different oximes.

5. **Conclusion**:
- The compound that will form only one oxime is the one that is an aldehyde. If the options provided include an aldehyde, that will be the correct answer.

### Final Answer:
The compound that will form only one oxime on reaction with NH2OH is the aldehyde.