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Identify (Z)-2-pentene :...

Identify (Z)-2-pentene :

A

B

C

D

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To identify (Z)-2-pentene, we will follow these steps: ### Step 1: Understand the Structure of 2-Pentene 2-Pentene is an alkene with the molecular formula C5H10. The double bond is located between the second and third carbon atoms in the chain. The structure can be represented as: ``` CH3-CH=CH-CH2-CH3 ``` ### Step 2: Identify the Groups Attached to the Double Bond In 2-pentene, the double bond connects the second and third carbon atoms. We need to identify the groups attached to these carbons: - **C2** (the second carbon) has: - CH3 (methyl group) - H (hydrogen atom) - **C3** (the third carbon) has: - CH2 (part of the ethyl group) - CH3 (methyl group) ### Step 3: Assign Priorities to the Groups According to the Cahn-Ingold-Prelog priority rules, we assign priorities based on the atomic number of the atoms directly attached to the double-bonded carbons: - For C2: - CH3 (C) has a higher priority than H (H). - For C3: - CH3 (C) has a higher priority than CH2 (C). ### Step 4: Determine the Configuration (Z or E) - If the higher priority groups on each carbon are on the same side of the double bond, the configuration is Z (from the German "zusammen," meaning together). - If they are on opposite sides, the configuration is E (from the German "entgegen," meaning opposite). In (Z)-2-pentene, both higher priority groups (CH3 from C2 and CH3 from C3) are on the same side of the double bond. ### Step 5: Write the Final Structure Thus, the structure of (Z)-2-pentene can be represented as: ``` CH3 | CH3-CH=CH-CH2-CH3 ``` Where the CH3 groups are on the same side of the double bond. ### Conclusion Therefore, (Z)-2-pentene is identified as the compound where the higher priority groups are on the same side of the double bond. ---
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Knowledge Check

  • Identify (Z) in the following series,

    A
    `CH_(2)=CH_(2)`
    B
    `CH_(3)-CH_(2)-OH`
    C
    `CH_(3)-CH_(2)-O-CH_(2)-CH_(3)`
    D
    `CH_(3)-CH_(2)-SO_(3)H`
  • Identify (Z) in the following reaction series, C_2H_5Ioverset("Alcoholic")underset("KOH")rarr(X)overset(Br_2)rarr (Y)overset(KCN)rarr (Z)

    A
    `CH_3-CH_2-CN`
    B
    `underset(CN)underset(|)CH_2-underset(CN)underset(|)CH_2`
    C
    `underset(Br)underset(|)CH_2-underset(CN)underset(|)CH_2`
    D
    `underset(Br)underset(|)CH=underset(CN)underset(|)"CH"`
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