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The galvanometer deflection , when key K...

The galvanometer deflection , when key `K_(1)` is closed but `K_(2)` is open equals `theta_(0)` (see figure ) On closing `k_(2)` also and adjusting `R_(2) ` to ` 5Omega` , the deflection in galvanometer becomes `(theta_(0))/(5)` the resistnce of the galvanometer is then , given by [Neglect the internal resistance of battery]:

Text Solution

Verified by Experts

The correct Answer is:
22
Deflection in galvanometer is proportional to galvanoeter current `theta_(0) prop ig rArr theta_(0)K=ig`
Situation 1 `K theta_(0)=(v)/(220+R)` ………(i)
Situation 2 `(Ktheta_0)/(5)=(v)/((220+(5R)/(5+R)))xx(5)/(5+R)`
From (i) and (2) `R=22 Omega`.
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