Home
Class 12
PHYSICS
The galvanometer deflection , when key K...

The galvanometer deflection , when key `K_(1)` is closed but `K_(2)` is open equals `theta_(0)` (see figure ) On closing `k_(2)` also and adjusting `R_(2) ` to ` 5Omega` , the deflection in galvanometer becomes `(theta_(0))/(5)` the resistnce of the galvanometer is then , given by [Neglect the internal resistance of battery]:

Text Solution

Verified by Experts

The correct Answer is:
22
Deflection in galvanometer is proportional to galvanoeter current `theta_(0) prop ig rArr theta_(0)K=ig`
Situation 1 `K theta_(0)=(v)/(220+R)` ………(i)
Situation 2 `(Ktheta_0)/(5)=(v)/((220+(5R)/(5+R)))xx(5)/(5+R)`
From (i) and (2) `R=22 Omega`.
Promotional Banner

Topper's Solved these Questions

  • JEE MAIN REVISION TEST 8 (2020)

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

  • JEE MAIN REVISION TEST 5 (2020)

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

  • JEE MAIN REVISION TEST- 16

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

Similar Questions

Explore conceptually related problems

100mA current gives a full scale deflection in a galvanometer of 2Omega resistance. The resistance connected with the galvanometer to convert it into a voltmeter to measure 5V is

As shown in the figure initially switch k1 is open and k2 is closed and deflection of galvanometer is x. Now both switch are closed then the deflection in galvanometer is x/5 (given R_H= 5Omega) . The resistance of galvanometer is

To locate null point deflection battery key (K_1) ios pressed before the galvanometer (K_2) Explanation why?

The resistances P,Q,R and S in the bridge shown are adjusted such that the deflection in the galvanometer G is zero when both the keys K_(1) and K_(2) are inserted. The galvanometer will show a momentary deflection if

To locate null point, deflection battery key K_(1) is pressed before the galvanometer key K_(2) . Explain why?

The deflection in a moving coil galvanometer falls from 50 divisions when a shunt of 2 Omega is applied. What is the resistance ( in ohms ) of the galvanometer ?

In the circuits shown in the figures, the galvanometers show no deflection. Find the ratio of R_(1) and R_(2) .

In the given potentiometer circuit length of the wire AB is 3 m and resistance is R = 4.5 Omega . The length AC for no deflection in galvanometer is

A galvanometer of 50 Omega resistance when connected across the terminals of a battery of emf 2V along with the resistance 200 Omega the deflection produced in the galvanometer is 10 divisions. If the total number of divisions on the galvanometer ·scale on either side of central zero is 30, then the maximum current that can pass through the galvanometer is

When a galvanometer is shunted with a 4Omega resistance, the deflection is reduced to 1//5 . If the galvanometer is further shounted with a 2Omega wire, the new deflection will be (assuming the main current remains the same)