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The stopping potential V(0) (in volt) a...

The stopping potential `V_(0)` (in volt) as a function of frequency (v) for a sodium emitter, is shown in the figure. The work function of sodium, from the data plotted in the figure, will be:
(Given : Planck’s constant)
`(h) = 6.63 xx10^(-34)Js" electron charge "e=1.6xx10^(-19)C`)

A

1.95 eV

B

2.12 eV

C

1.66 eV

D

1.82

Text Solution

Verified by Experts

The correct Answer is:
C
`W=hv_(0)=6.63xx10^(-34)xx10^(14)xx4J`
`W=6.63xx10^(20)Jxx4=(4xx6.63xx10^(-20))/(1.6xx10^(-19))eV=1.66eV`
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