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The stopping potential V(0) (in volt) a...

The stopping potential `V_(0)` (in volt) as a function of frequency (v) for a sodium emitter, is shown in the figure. The work function of sodium, from the data plotted in the figure, will be:
(Given : Planck’s constant)
`(h) = 6.63 xx10^(-34)Js" electron charge "e=1.6xx10^(-19)C`)

A

1.95 eV

B

2.12 eV

C

1.66 eV

D

1.82

Text Solution

Verified by Experts

The correct Answer is:
C
`W=hv_(0)=6.63xx10^(-34)xx10^(14)xx4J`
`W=6.63xx10^(20)Jxx4=(4xx6.63xx10^(-20))/(1.6xx10^(-19))eV=1.66eV`
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the stopping potential V_(o) (in volt) as a function of frequency (v) for a soidum emitter, is shown in the figure. The work function of sodium from the data plotted in the figure. Will be: [ given plank's constant (h)=6.63xx10^(-34)Js , electron charge e=1.6xx10^(-19)C )

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Knowledge Check

  • A student performs an experiment on photoelectric effect using two materials A and B. A plot of stopping potential (V_(0)) vs freqency (v) is as shown in the figure. The value of h obtained from the experiment for both A and B respectively is (Given electric charge of an electron =1.6xx10^(-19)C)

    A
    `3.2xx10^(-34)Js,4xx10^(-34)Js`
    B
    `6.4xx10^(-34)Js,8xx10^(-34)Js`
    C
    `1.2xx10^(-34)Js,3.2xx10^(-34)Js`
    D
    `4.2xx10^(-34)Js,5xx10^(-34)Js`

  • Calculate the energy in joule corresponding to light of wavelength 45 nm : ("Planck's constant "h=6.63 xx 10^(-34)" Js: speed of light :"c =3 xx 10^8 "ms"^(-1)) .

    A
    `6.67xx10^(15)`
    B
    `6.67xx10^(11)`
    C
    `4.42 xx10^(-15)`
    D
    `4.42 xx10^(-18)`

  • in the question number 63, the frequency of emitted photon due to the given transition is (h=6.64xx10^(-34)Js,1eV=1.6xx10^(-19)J)

    A
    `2.46xx10^(10)Hz`
    B
    `2.46xx10^(12)Hz`
    C
    `2.46xx10^(15)Hz`
    D
    `2.46xx10^(18)Hz`

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