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The plane ax+by=0 is rotated through an ...

The plane `ax+by=0` is rotated through an angle `alpha` about its line of intersection with the plane `z=0`. Show that the equation to the plane in new position is `ax+bypmzsqrt(a^2+b^2)tanalpha=0`.

A

`ax + by pm z sqrt(a ^(2) + b ^(2)) tan alpha =0`

B

` (ax+ by) sqrt(a ^(2)+b ^(2)) pm z tan alpha =0`

C

`tan alpha (ax +by) pm z sqrt(a ^(2)+b ^(2)) =0`

D

`ax + by pm sqrt(a ^(2) + b ^(2)) = tan alpha `

Text Solution

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The correct Answer is:
A
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