Home
Class 12
CHEMISTRY
Number of unit cells in 4g of X(atomic m...

Number of unit cells in 4g of X(atomic mass=40). Which crystallises in bcc pattern in `(N_(0)="Avogadro number")`

A

`0.1 N_(A)`

B

`2xx0.1 N_(A)`

C

`(0.1N_(A))/(2)`

D

`2xxN_(A)`

Text Solution

AI Generated Solution

To find the number of unit cells in 4 g of element X that crystallizes in a body-centered cubic (BCC) pattern, we can follow these steps: ### Step 1: Calculate the number of moles of X We can use the formula for calculating the number of moles: \[ n = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \] Given: ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THE SOLID STATE

    VMC MODULES ENGLISH|Exercise LEVEL-2|50 Videos

  • THE SOLID STATE

    VMC MODULES ENGLISH|Exercise LEVEL-2 (Numerical Value Type for JEE Main )|15 Videos

  • THE SOLID STATE

    VMC MODULES ENGLISH|Exercise LEVEL-0 ( Long Answer Type)|6 Videos

  • SURFACE CHEMISTRY

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE|9 Videos

  • THEORY OF SOLUTIONS

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|31 Videos

Similar Questions

Explore conceptually related problems

Number of unit cells in 10 g NaCl

Number of atoms in fcc unit cell is

The number of atoms per unit cell in bcc lattice is

In a cubic lattice each edge of the unit cell is 400 pm. Atomic weigth of the element is 60 and its density is 625g//c.c. Avogadro number = 6times10^(23) .The crystal lattice is

An element of atomic mass 40 occurs in fcc structure with a cell edge of 540 pm. Calculate the Avogadro's number if density is 1.7gm//cm^(3) .

By X-ray diffraction it is found that nickel ("at mass"=59g "mol"^(-1)) , crystallizes in ccp. The edge length of the unit cell is 3.5 Å . If density of Ni crystal is 9.0g//cm^(3) , then value of Avogadro's number from the data is:

The number of carbon atoms per unit cell of diamond unit cell is

The number of carbon atoms per unit cell of diamond unit cell is

An element of atomic mass 90 occurs in fce structure with cell edge of 500 pm. Calculate the Avogadro's number if the density is 4.2g cm^(-3)

How many unit cells are present in 5.0 gm of crystal AB (formula mass of AB =40) having rock salt type structure ? ( N_(A) = Avogadro 's no.)

Home
Profile