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Find (a) time of flight , (b) Max.height...

Find (a) time of flight , (b) Max.height (c ) Horizontal range of projectile projected with speed (v) making an angle ` theta` with the horizontal direction from ground.

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AI Generated Solution

To solve the problem of finding the time of flight, maximum height, and horizontal range of a projectile launched with speed \( v \) at an angle \( \theta \) with respect to the horizontal, we can follow these steps: ### Step 1: Determine the Components of Initial Velocity The initial velocity \( v \) can be resolved into horizontal and vertical components: - Horizontal component (\( v_x \)): \[ v_x = v \cos \theta \] ...
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At a height of 45 m from ground velocity of a projectile is, v = (30hati + 40hatj) m//s Find initial velocity, time of flight, maximum height and horizontal range of this projectile. Here hati and hatj are the unit vectors in horizontal and vertical directions.

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Knowledge Check

  • If R and H represent horizontal range and maximum height of the projectile, then the angle of projection with the horizontal is

    A
    `tan^(-1)((H)/(R ))`
    B
    `tan^(-1)((2H)/(R ))`
    C
    `tan^(-1) ((4H)/(R ))`
    D
    `tan^(-1) ((4H)/(H))`

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