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In the figure shown, m(1) = 10kg, m(2) =...

In the figure shown, `m_(1)` = 10kg, `m_(2)` = 6kg, `m_(3)` = 4kg. If `T_(3)` = 40 N, `T_(2)` = ?

A

(a)13 N

B

(b)32 N

C

(c)25 N

D

(d)35 N

Text Solution

Verified by Experts

The correct Answer is:
B
Acceleration of system `= (40)/(10 + 6 + 4) = 2m//s^(2) T_(3) - T_(2) = m_(2) (2) :. T_(2) = 32 N`
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