Home
Class 12
PHYSICS
In the figure shown, a particle of small...

In the figure shown, a particle of small mass m is joined to a very heavy mass M (M >> m) by a light string passing over a light pulley. The total downward force on the pulley by the string is :

A

(a)mg

B

(b)2 mg

C

(c)4 mg

D

(d)(M + m) g

Text Solution

Verified by Experts

The correct Answer is:
C
m moves upwards with acceleration `a = ((M -m)g)/((M + m)) = ((1 - (m)/(M))/(1 +(m)/(M)))g`,
`M gt gt m implies (m)/(M) = 0`
`:. A = g` T - mg = ma = mg `implies T = 2mg`
Downward force on pulley by string = 2T = 4 mg
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • DYNAMICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise LEVEL 2 ( NUMERICAL TYPE FOR JEE MAIN )|16 Videos

  • DYNAMICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise JEE Main (Archive) Level - I|29 Videos

  • DYNAMICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise LEVEL 1|75 Videos

  • DC CIRCUIT

    VMC MODULES ENGLISH|Exercise JEE ADVANCED ARCHIVE|68 Videos

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-G|10 Videos

Similar Questions

Explore conceptually related problems

A particle of small m is joined to a very heavy body by a light string passing over a light pulley. Both bodies are free to move. The total downward force on the pulley is

Two masses m and M(m lt M) are joined by a light string passing over a smooth and light pulley (as shown)

Knowledge Check

  • A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by

    A
    `sqrt2 Mg`
    B
    `sqrt2 mg`
    C
    `sqrt((M+m)^(2)+m^(2)g)`
    D
    `sqrt((M+m)^(2)+M^(2)g)`

    • Similar Questions

    Explore conceptually related problems

    Two masses m and M(gt m) are joined by a light string passing over a smooth light pulley. The centre of mass of the system moves with an acceleration

    Two identical masses are attached by a light string that passes over a small pulley, as shown . The table and the pulley are frictionless. The hanging block is moving

    A block of mass M is placed on a rough horizontal surface. It is connected by means of a light inextensible string passing over a smooth pulley . The other end of string passing over a smooth pulley. The other end of string is connected to a block of mass m. There is no friction between vertical surface and block m If the coefficient of friction of friction mu is less than the above value, then downward acceleration of block m is

    Two unequal masses are connected by a very light string over a clamped light smooth pulley. Find the acceleration of the system and the tension in the string.

    A block of mass M is placed on a rough horizontal surface. It is connected by means of a light inextensible string passing over a smooth pulley . The other end of string passing over a smooth pulley. The other end of string is connected to a block of mass m. There is no friction between vertical surface and block m If the whole system ( horizontal surface + blocks ) accelerates towards right the value of maximum on the horizontal surface is

    A string of negligible mass going over a clamped pulley of mass m supports a block of mass M as shown in the figure. The force on the pulley by the clamp is given by

    A block of mass M placed on a frictionless horizontal table is pulled by another block of mass m hanging vertically by a massless string passing over a frictionless pulley. The tension in the string is :

    Home
    Profile