A wave equation which given the dispplacement along the y-direction is given by ,
`y = 10^(-4)sin (60t +2x)`
where x and y are in matre and t is time in second. This represents a wave

Options

A. traveling with a velocity of 30 m/s in the negative x-direction
B. of wavelength `pim`
C. of frequency `30//piHz`
D. of amplitude `10^(-4)m` travelling along the negative x-direction.

Answer

A, B, C, D

Explanation

`y=10^(-4) sin(60t+2x)` Comparing the given equation with the standard wave equation travelling in negative x- direction.
`y=a sin (omegat+kx)` We get amplitude `a=10^(-4)m`
Also, `omega=60 therefore 2pif=60 implies f=(30)/(pi) Hz`
Also, ` k=2 implies (2pi)/(lambda)=2 implies lambda=pim`< We know that `v=flambda=(30)/(pi)xxpi=30 m//s`