Home
Class 12
PHYSICS
A particle moves along the X-axis x=0 to...

A particle moves along the X-axis x=0 to x=5 m under the influence of a force given by `F=10-2x+3x^(2)`. Work done in the process is

Text Solution

Verified by Experts

The correct Answer is:
[(A – P, Q, R, T); (B – Q, S) (C – P, Q, R, S) (D – P, R, T)]

The particle will experience an attractive force towards x = 0 in the region `| x | < a`
If `0 < x < a implies F = -ve and if x > a implies F = + ve`
The particle will oscillate about `x = -a` if U is min at `x = -a` and U at `x = -a < (U_0)/4`
Also `F = (-d U)/(dx)`
`implies (A) F= (2 U_0x)/(a^2)[1 - (x/a)^2] " "(B) F = -(U_0x)/(a^2)`
`(C ) F = - (U_0x)/(a^2)(1 - (x^2)/a^2))e^((-x^2)/(a^2)) " "(D) F = - (U_0)/(2a) (1 - x^2)/(a^2))` .
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ENERGY & MOMENTUM

    VMC MODULES ENGLISH|Exercise JEE ADVANCE (ARCHIVE) - FILL IN THE BLANKS TYPE|1 Videos
  • ENERGY & MOMENTUM

    VMC MODULES ENGLISH|Exercise JEE ADVANCE (ARCHIVE) - TRUE/FALSE TYPE|1 Videos
  • ENERGY & MOMENTUM

    VMC MODULES ENGLISH|Exercise JEE ADVANCE (ARCHIVE) - ASSERTION & REASON TYPE|1 Videos
  • ELECTROSTATICS

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|89 Videos
  • GASEOUS STATE & THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise JEE ADVANCED (ARCHIVE )|111 Videos

Similar Questions

Explore conceptually related problems

A particle moves along X-axis from x=0 to x=1 m under the influence of a force given by F=3x^(2)+2x-10. Work done in the process is

A particle moves along X-axis from x=0 to x=1 m under the influence of a force given by F=3x^(2)+2x-10. Work done in the process is

A particle moves along the X-axis from x=0 to x=5 m under the influence of a force given by F=7-2x+3x^(2). Find the work done in the process.

A particle moves along the x-axis from x=0 to x=5m under the influence of a given by F =7-2x + 3x^(2) . The work done by the applied force to the particle is.

A particle moves along x-axis from x=0 to x=2 m under the influence of a force F (in N) given by F=3x^(2)+2x-5. Calculate the work done

A particle is moving along the axis under the influnence of a force given by F = -5x + 15 . At time t = 0 , the particle is located at x = 6 and having zero velocity it take 0.5 second to reach the origin for the first time. The equation of motion of the particle can be respected by

A particle moves along x - axis under the action of a position dependent force F=(5x^(2)-2x)N . Work done by force on the particle when it moves from origin to x = 3 m is

A particale moves under the effect of a force F = Cx from x = 0 to x = x_(1) . The work down in the process is

A particle of mass m moves on positive x-axis under the influence of force acting towards the origin given by -kx^2 hat i. If the particle starts from rest at x=a, the speed it will attain when it crosses the origin is

A particle of mass m moves on the x-axis under the influence of a force of attraction towards the origin O given by F=-(k)/(x^(2))hat(i) . If the particle starts from rest at x = a. The speed of it will attain to reach at distance x from the origin O will be