Which one of the following is a correct set?

Options

A. `H_(2)O, sp^(3)` angular
B. `BCl_(3), sp^(3)`, angular
C. `NH_(4)^(+), dsp^(2)`, square planar
D. `CH_(4), dsp^(2)`, tetrahedral

Explanation

To determine which of the given options is a correct set regarding hybridization and molecular geometry, we will analyze each option step by step.

### Step-by-Step Solution:

1. **Option A: H₂O (Water)**
- **Central Atom**: Oxygen
- **Valence Electrons**: Oxygen has 6 valence electrons.
- **Bonds**: Forms 2 sigma bonds with 2 hydrogen atoms.
- **Lone Pairs**: 2 lone pairs remain on oxygen.
- **Steric Number Calculation**:
- Sigma bonds: 2
- Lone pairs: 2
- Total Steric Number = 2 (sigma bonds) + 2 (lone pairs) = 4
- **Hybridization**: With a steric number of 4, the hybridization is sp³.
- **Molecular Geometry**: The shape is bent or angular due to the presence of lone pairs.
- **Conclusion**: This option is correct.

2. **Option B: BCl₃ (Boron Trichloride)**
- **Central Atom**: Boron
- **Valence Electrons**: Boron has 3 valence electrons.
- **Bonds**: Forms 3 sigma bonds with 3 chlorine atoms.
- **Lone Pairs**: No lone pairs on boron.
- **Steric Number Calculation**:
- Sigma bonds: 3
- Lone pairs: 0
- Total Steric Number = 3 (sigma bonds) + 0 (lone pairs) = 3
- **Hybridization**: With a steric number of 3, the hybridization is sp².
- **Molecular Geometry**: The shape is trigonal planar.
- **Conclusion**: The given option states sp³, which is incorrect. This option is wrong.

3. **Option C: NH₄⁺ (Ammonium Ion)**
- **Central Atom**: Nitrogen
- **Valence Electrons**: Nitrogen has 5 valence electrons.
- **Bonds**: Forms 4 sigma bonds with 4 hydrogen atoms.
- **Lone Pairs**: No lone pairs on nitrogen.
- **Steric Number Calculation**:
- Sigma bonds: 4
- Lone pairs: 0
- Total Steric Number = 4 (sigma bonds) + 0 (lone pairs) = 4
- **Hybridization**: With a steric number of 4, the hybridization is sp³.
- **Molecular Geometry**: The shape is tetrahedral.
- **Conclusion**: The given option states dsp², which is incorrect. This option is wrong.

4. **Option D: CH₄ (Methane)**
- **Central Atom**: Carbon
- **Valence Electrons**: Carbon has 4 valence electrons.
- **Bonds**: Forms 4 sigma bonds with 4 hydrogen atoms.
- **Lone Pairs**: No lone pairs on carbon.
- **Steric Number Calculation**:
- Sigma bonds: 4
- Lone pairs: 0
- Total Steric Number = 4 (sigma bonds) + 0 (lone pairs) = 4
- **Hybridization**: With a steric number of 4, the hybridization is sp³.
- **Molecular Geometry**: The shape is tetrahedral.
- **Conclusion**: The given option states dsp², which is incorrect. This option is wrong.

### Final Conclusion:
The only correct option is **Option A: H₂O**, which has sp³ hybridization and an angular shape.