Home
Class 12
CHEMISTRY
a. A cylinder of gas is assumed to conta...

a. A cylinder of gas is assumed to contain `11.2 kg` of butane. If a normal family needs `20000kJ` of energy per day for cooking, how long will the cylinder last? Given that the heat of combustion of butane is `2658 kJ mol^(-1)`.

Text Solution

Verified by Experts

(A) `C_(4)H_(10)(g) + 13/2 O_(2)(g) to 4CO_(2)(g) + 5H_(2)O(g)`
58 gm butane `to` 2658 kJ energy
11200 gm butane `=2658/58 xx 11200` kJ energy
Number of days `=(2568)/58 xx 11200/20000 = 26` days
(B) Number of days `=26 xx 0.67 = 17` days
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise LEVEL-0 (SHORT ANSWER TYPE-II (3 MAKRS))|6 Videos

  • THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise LEVEL-0 (LONG ANSWER TYPE (5 MARKS))|6 Videos

  • THERMODYNAMICS

    VMC MODULES ENGLISH|Exercise JEE ADVANCED (ARCHIVE)|44 Videos

  • THERMOCHEMISTRY

    VMC MODULES ENGLISH|Exercise JEE ADVANCED (ARCHIVE)|31 Videos

  • THERMODYNAMICS & THERMOCHEMISTRY

    VMC MODULES ENGLISH|Exercise Impeccable|48 Videos

Similar Questions

Explore conceptually related problems

A cylinder of gas is assumed to contain 11.6 kg of butane (C_4H_10) . If a normal family needs 20000kJ of energy per day, then the cylinder will last for : (Given that ΔH for combustion of butane is – 2658kJ)

The heat of combustion of butane is 2658 kl. A cylinder of LPG gas (containing only butane) is assumed to contain 14.2 kg of butane. If a normal family needs 18000 kJ of energy per day for cooking, how long the cylinder will last?

Knowledge Check

  • How much heat is evolved if 3.2 g of methane is burnt and if the heat of combustion of methane is -880" kJ mol"^(-1) ?

    A
    88 kJ
    B
    264 kJ
    C
    176 kJ
    D
    440 kJ

    • Similar Questions

    Explore conceptually related problems

    A gobar gas plant produces methane and supplies to the families. If a family requires 15,000 kJ of energy per day, how many days will the quote of 10 kg will last ? (Delta_(c)H "of" CH_(4) = - "1665 kJ "mol^(-1))

    A gobar gas plant produces methane and supplies to the families. If a family requires 15000 kJ of energy per day, how many days will the quota of 20 kg will last (Delta_(c) H of CH_(4) = -1665 kJ mol^(-1) ).

    An athlete is given 180 g of glucose (C_(6)H_(12)O_(6)) . He utilises 50% of the energy due to internal combustion in the body. In order to avoid storage of energy in the body, calculate the masss of water he would need to perspire. Given enthalpy of combustion of glucose is -2800 kJ mol^(-1) and enthalpy of evaporation of water is 44 kJ mol^(-1)

    An athlete is given 180 g of glucose (C_(6)H_(12)O_(6)) . He utilises 50% of the energy due to internal combustion in the body. In order to avoid storage of energy in the body, calculate the masss of water he would need to perspire. Given enthalpy of combustion of glucose is -2800 kJ mol^(-1) and enthalpy of evaporation of water is 44 kJ mol^(-1)

    A cylinder of cooking gas is assumed to contain 11.2 kg of butane. The thermo chemical equation for the combustion of butane is : C_(4)H_(10)(g)+(13)/(2)O_(2)(g)rarr 4CO_(2)(g)+5H_(2)O(l) , Delta H = -2658 kJ If a family needs 15000 kJ of energy per day for cooking, how would the cylinder last ?

    Gobar gas obtained by bacterial fermentation of animal refuse contains mainly methane. The heat of combustion of methane to CO_2 and water (gas) is given by CH_4(g) + 2O_2(g) to CO_2(g) + 2H_2O (g) + 809 kJ . How much gobar gas would have to be produced per day for a small village community of 100 families, if we assume that each family has to be supplied 20,000 kJ of energy per day to meet all its needs and that the methane content in gobar gas is 80% by weight?

    An average person eats carbohydrates equivalent to 0.350 kg of glucose and 0.200 kg of fats every day. The person needs about 10000 kJ per day. If the body consumes carbohydrates preferentially, how much will his weight increase per year assuming that only 50% of the excess fats are excreted. Give that the heat of combustion of glucose is 2900 kJ and combustion of fats produces energy equivalent to 39000 kJ kg^(-1) ?

    Home
    Profile