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a. A cylinder of gas is assumed to conta...

a. A cylinder of gas is assumed to contain `11.2 kg` of butane. If a normal family needs `20000kJ` of energy per day for cooking, how long will the cylinder last? Given that the heat of combustion of butane is `2658 kJ mol^(-1)`.

Text Solution

Verified by Experts

(A) `C_(4)H_(10)(g) + 13/2 O_(2)(g) to 4CO_(2)(g) + 5H_(2)O(g)`
58 gm butane `to` 2658 kJ energy
11200 gm butane `=2658/58 xx 11200` kJ energy
Number of days `=(2568)/58 xx 11200/20000 = 26` days
(B) Number of days `=26 xx 0.67 = 17` days
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Knowledge Check

  • How much heat is evolved if 3.2 g of methane is burnt and if the heat of combustion of methane is -880" kJ mol"^(-1) ?

    A
    88 kJ
    B
    264 kJ
    C
    176 kJ
    D
    440 kJ