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The work done during the expansion of a ...

The work done during the expansion of a gas from `4dm^(3)` to `6dm^(3)` against at constant external pressure of 3 atm is (1 L atm = 101.32 J)

A

`-6J`

B

`-608 J`

C

`304 J`

D

`-304 J`

Text Solution

Verified by Experts

The correct Answer is:
B

Work done `(W = -p_(ext) (V_(2)-V_(1))`
`=-3 xx (6-4) = -6 L atm`
`=-6 xx 101.32 J (therefore 1L atm = 101.32 J)`
`=-607.92 ~~ -608 J`
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VMC MODULES ENGLISH-THERMODYNAMICS-LEVEL-1
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