Home
Class 12
CHEMISTRY
In chemical equilibrium, the value of De...

In chemical equilibrium, the value of `Delta n` (number of molecules), is negative, then the relationship between `K_(p) "and" K_(c)` will be

A

`K_(P)-K_(c) = 0`

B

`K_(c) = K_(P) xx (RT)^(+Deltan)`

C

`K_(P) = K_(c) xx (RT)^(-Deltan)`

D

`K_(c) = 1/K_(p)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the relationship between \( K_p \) and \( K_c \) when the value of \( \Delta n \) (the change in the number of moles of gas) is negative, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definitions**: - \( K_p \) is the equilibrium constant in terms of partial pressures. - \( K_c \) is the equilibrium constant in terms of molar concentrations. - \( \Delta n \) is defined as the difference between the number of moles of gaseous products and the number of moles of gaseous reactants. 2. **Write the Relationship**: - The relationship between \( K_p \) and \( K_c \) is given by the formula: \[ K_p = K_c \cdot R T^{\Delta n} \] where \( R \) is the universal gas constant and \( T \) is the temperature in Kelvin. 3. **Substituting \( \Delta n \)**: - Since it is given that \( \Delta n \) is negative, we can denote it as \( \Delta n < 0 \). - This means that when we substitute \( \Delta n \) into the equation, we have: \[ K_p = K_c \cdot R T^{\Delta n} \] 4. **Rearranging the Equation**: - To express \( K_c \) in terms of \( K_p \), we can rearrange the equation: \[ K_c = \frac{K_p}{R T^{\Delta n}} \] - Since \( \Delta n \) is negative, \( T^{\Delta n} \) can be rewritten as \( \frac{1}{T^{|\Delta n|}} \), where \( |\Delta n| \) is the positive value of \( \Delta n \). 5. **Final Relationship**: - Therefore, we can express the relationship as: \[ K_c = K_p \cdot \frac{1}{R T^{|\Delta n|}} \] - This indicates that \( K_c \) is inversely related to \( K_p \) when \( \Delta n \) is negative. ### Conclusion: When \( \Delta n \) is negative, the relationship between \( K_p \) and \( K_c \) can be summarized as: \[ K_c = \frac{K_p}{R T^{|\Delta n|}} \]

To solve the question regarding the relationship between \( K_p \) and \( K_c \) when the value of \( \Delta n \) (the change in the number of moles of gas) is negative, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definitions**: - \( K_p \) is the equilibrium constant in terms of partial pressures. - \( K_c \) is the equilibrium constant in terms of molar concentrations. - \( \Delta n \) is defined as the difference between the number of moles of gaseous products and the number of moles of gaseous reactants. ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise Level 2|65 Videos
  • CHEMICAL EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise JEE Main (Archive)|24 Videos
  • CHEMICAL EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise Level 0 LA|6 Videos
  • CHEMICAL BONDING-I & II

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|98 Videos
  • CHEMICAL KINETICS

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|52 Videos

Similar Questions

Explore conceptually related problems

What is the relationship between K_p and K_c ?

What is the relationship between pK_(a) and K_(a) of an acid ?

What are K_(c) "and" K_(P) ?

In a chemical equilibrium, K_p = K_c is valid if

In a chemical equilibrium, K_(c)=K_(p) when

At equilibrium, the value of equilibrium constant K is

For A+BhArrC+D , the equilibrium constant is K_(1) and for C+DhArrA+B , the equilibrium constant is K_(2) . The correct relation between K_(1) and K_(2) is

Which is the correct relationship between DeltaG^(@) and equilibrium constant K_(p) ?

VMC MODULES ENGLISH-CHEMICAL EQUILIBRIUM-Level 1
  1. Ammonium carbamate decomposes as : NH(2)COONH(4) (s) rarr 2NH(3)(g) ...

    Text Solution

    |

  2. 4 moles each of SO(2) "and" O(2) gases are allowed to react to form SO...

    Text Solution

    |

  3. In chemical equilibrium, the value of Delta n (number of molecules), i...

    Text Solution

    |

  4. K(p)//K(c) for the reaction CO(g)+1/2 O(2)(g) hArr CO(2)(g) is

    Text Solution

    |

  5. The equilibrium constant (K(c)) of the reaction A(2)(g) + B(2)(g) rarr...

    Text Solution

    |

  6. A+B=C+D. If initially the cocentration of A and B are both equal but a...

    Text Solution

    |

  7. Which of the following is correct for the reaction? N(2)(g) + 3H(2)(g)...

    Text Solution

    |

  8. The equilibrium constant of a reaction is 300, if the volume of the re...

    Text Solution

    |

  9. Partial pressure of O(2) in the reaction 2Ag(2)O(s) hArr 4Ag(s)+O(2)...

    Text Solution

    |

  10. The compounds A and B are mixed in equimolar proportion to form the pr...

    Text Solution

    |

  11. In which of the following reactions, the concentration of product is h...

    Text Solution

    |

  12. The equilibrium: P(4)(g)+6Cl(2)(g) hArr 4PCl(3)(g) is attained by ...

    Text Solution

    |

  13. Consider the following reaction equilibrium N(2)(g) + 3H(2)(g) hArr...

    Text Solution

    |

  14. A reversible reaction is one which :

    Text Solution

    |

  15. In a reaction the rate of reaction is proportional to its active mass,...

    Text Solution

    |

  16. In the equilibrium,AB(s) rarr A(g) + B(g), if the equilibrium concentr...

    Text Solution

    |

  17. According to law of mass action, for the reaction :2A + B rarr Product...

    Text Solution

    |

  18. For the system 3A +2B hArr C the expression for equilibrium constant K...

    Text Solution

    |

  19. 5 mole of X are mixed with 3 moles of Y. At equilibrium for the reacti...

    Text Solution

    |

  20. The equilibrium constant of a reversible reaction at a given temperatu...

    Text Solution

    |