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A particle of mass 2 kg located at the p...

A particle of mass 2 kg located at the position `(hati+hatj)` m has a velocity 2 `(+hati-hatj+hatK) m//s`. Its angular momentum about z-axis in `(kg-m^(2)//s)` is

A

zero

B

10

C

`4sqrt(3)`

D

`4sqrt(6)`

Text Solution

Verified by Experts

The correct Answer is:
D
`vecL= vecr xx mvecV = 2 xx 2 |{:(hati, hatj, hatk),(1,1,0),(1,-1,1):}|=4(hati - hatj - 2hatk) rArr |vecL| = 4sqrt(6) kg m^(2)//s`
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A particle of mass 2 kg located at the position (hati + hatj)m has velocity 2(hati - hatj + hatk) m//s . Its angular momentum about Z-axis in kg m^(2)//s is

A particle of mass 2 kg located at the position (hat i+ hat k) m has a velocity 2(+ hat i- hat j + hat k) m//s . Its angular momentum about z- axis in kg-m^(2)//s is :

Knowledge Check

  • Two particles of masses 1 kg and 3 kg have position vectors 2hati+3hatj+4hatk and-2hati+3hatj-4hatk respectively. The centre of mass has a position vector

    A
    `hati+3hatj-2hatk`
    B
    `-hati-3hatj-2hatk`
    C
    `-hati+3hatj+2hatk`
    D
    `-hati+3hatj-2hatk`

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