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For the reaction: 2A+Bto A(2)B the r...

For the reaction:
`2A+Bto A_(2)B`
the rate = `k[A][B]^(2)` with k `= 2.0xx10^(-6) mol^(-2) L^(2)s^(-1)`. Calculate the initial
rate of the reaction when `[A] =0.1 mol L^(-1),[b] = 0.2mol L^(-1)`. Calculate
the rate of reaction after [A] is reduced to `0.06 mol L^(-1)`

Text Solution

Verified by Experts

Rate `=k[A][B]^(2)=2xx10^(-6) [0.1] [0.2]^(2)`
`=8xx10^(-9)" mol L"^(-1)" sec"^(-1)`
`[A]_("Final") =0.06" mol L"^(-1)`
Ratio of A to B is 2:1
`[B]_("Final") =0.2-((0.04)/(2))=0.18" mol L"^(-1)`
Rate `=(2xx10^(-6))(0.06)(0.18)^(2)`
`=3.89xx10^(-9)" mol L"^(-1)" sec"^(-1)`
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