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Consider a buffer solution containing 0....

Consider a buffer solution containing `0.1mol` each of acetic and sodium acetate in `1.0L` of solution, `0.01mol` of `NaOH` is gradually added to this buffer solution. Calculate the average buffer capacity of the solution and as well as initial and final buffer capacity. `[K_(a) = 2 xx 10^(-5)] pK_(a) = 4.7`

Text Solution

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pH of the solution is given by , `pH = pK_(a) + log_(10). (["salt"])/(["acid"]) `
Initial pH of solution , `pH = pK_(a) + log_(10) . (0.1)/ (0.1) = 4. 7`
When `0.01` M NaOH is added , [salt] = `0.11` M and [acid ] = `0.09` M
`rArr` Final pH of solution : `pH = pK_(a) + log_(10) . (0.11)/(0.09) = 4.787`
`rArr [H^(+)] = K_(a) (["acid"])/(["salt"]) = 2 xx 10^(-5) xx (0.09)/(0.11) = 1.64 xx 10^(-5) M`
Thus , `beta_("Avg.") = (Delta n)/(Delta(pH)) = (0.01)/(0.087) = 0.1148`
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