The theoretical volume of `O_(2)(g)` that can be obtained by decomposition of 1L of a `H_(2)O_(2)` solution at N.T.P is known as its volume strength. Calculate volume strength of `2 M H_(2)O_(2)` solution.

Explanation

To calculate the volume strength of a 2 M H₂O₂ solution, we can follow these steps:

### Step 1: Write the balanced chemical equation for the decomposition of H₂O₂.
The decomposition of hydrogen peroxide (H₂O₂) can be represented by the following balanced equation:

\[ 2 \, \text{H}_2\text{O}_2 \, \rightarrow \, 2 \, \text{H}_2\text{O} + \text{O}_2 \]

This equation shows that 2 moles of H₂O₂ produce 1 mole of O₂.

### Step 2: Determine the moles of H₂O₂ in 1 liter of the solution.
Given that the molarity of the H₂O₂ solution is 2 M, this means there are 2 moles of H₂O₂ in 1 liter of the solution.

### Step 3: Calculate the moles of O₂ produced.
From the balanced equation, we see that 2 moles of H₂O₂ produce 1 mole of O₂. Therefore, the moles of O₂ produced from 2 moles of H₂O₂ will be:

\[ \text{Moles of O}_2 = \frac{2 \, \text{moles of H}_2\text{O}_2}{2} = 1 \, \text{mole of O}_2 \]

### Step 4: Calculate the volume of O₂ at NTP.
At Normal Temperature and Pressure (NTP), 1 mole of any gas occupies 22.4 liters. Therefore, the volume of O₂ produced from 1 mole is:

\[ \text{Volume of O}_2 = 1 \, \text{mole} \times 22.4 \, \text{L/mole} = 22.4 \, \text{L} \]

### Step 5: Determine the volume strength.
The volume strength of a solution is defined as the volume of O₂ (in liters) that can be obtained from the decomposition of 1 liter of the solution. Since we calculated that 1 liter of 2 M H₂O₂ produces 22.4 liters of O₂, the volume strength is:

\[ \text{Volume Strength} = 22.4 \, \text{L} \]

### Final Answer:
The volume strength of the 2 M H₂O₂ solution is **22.4 liters**.

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