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The solubility product of CaF(2) " is " ...

The solubility product of `CaF_(2) " is " 3.9 xx 10^(-11) " at " 25^(@) C `. What is the solubility of this salt in grams/litre of `0.1` M NaF solution ?

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To solve the problem, we need to find the solubility of calcium fluoride (CaF₂) in a 0.1 M NaF solution, given that the solubility product (Ksp) of CaF₂ is 3.9 x 10^(-11) at 25°C. Here's a step-by-step solution: ### Step 1: Write the dissociation equation for CaF₂ Calcium fluoride dissociates in water as follows: \[ \text{CaF}_2 (s) \rightleftharpoons \text{Ca}^{2+} (aq) + 2 \text{F}^- (aq) \] ### Step 2: Define the solubility (s) Let the solubility of CaF₂ in the solution be \( s \) (in moles per liter). Therefore: ...
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Knowledge Check

  • The solubility product of MgF_(2) is 7.4xx10^(-11) . Calculate the solubility of MgF_(2) in 0.1 M NaF solution

    A
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    B
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    C
    `1xx10^(-3)`
    D
    `1xx10^(-9)`
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