Home
Class 12
PHYSICS
A ring rotates about z axis as shown in ...

A ring rotates about z axis as shown in figure. The plane of rotation is xy. At a certain instant the acceleration of a particle P (shown in figure) on the ring is `(6hat(i)-8hat(j)) m//s^(2)`. Find the angular acceleration of the ring & the abgular velocity at that instant. Radius of the ring is 2m.

Text Solution

Verified by Experts

`-3 hatk" rad/s"^(2), -2 hatk" rad/s"`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • Motion in Straight Line

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-A|11 Videos
  • Motion in Straight Line

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-B|10 Videos
  • Motion in Straight Line

    VMC MODULES ENGLISH|Exercise SOLVED EXAMPLES|20 Videos
  • MOTION IN A STRAIGHT LINE & PLANE

    VMC MODULES ENGLISH|Exercise IMPECCABLE|52 Videos
  • Motion in Two Dimensions

    VMC MODULES ENGLISH|Exercise MCQ|2 Videos

Similar Questions

Explore conceptually related problems

A wheel is rolling on a horizontal plane. At a certain instant it has a velocity v and acceleration a of CM as shown in figure . Acceleration of

A ring of radius R is rotating about axis of ring such that angular velocity is given as = 5t. Find acceleration of a point P on rim after 5 sec

A ring of radius R rolls on a horizontal surface with constant acceleration a of the centre of mass as shown in figure. If omega is the instantaneous angular velocity of the ring. Then the net acceleration of the point of contact of the ring with gound is

A smooth ring of mass m and radius R = 1 m is pulled at P with a constant acceleration a= 4 ms^(-2) on a horizontal surface such that the plane of the ring lies on the surface. Find the angular acceleration of the ring at the given position. (in rad//s^(2) )

Velocity of a particle at some instant is v=(3hat i + 4hat j + 5hat k) m//s . Find speed of the particle at this instant.

The velocity and acceleration vectors of a particle undergoing circular motion are v = 2 hat(i) m//s and a = 2 hat(i)+4 hat(j)m//s^(2) respectively at some instant of time. The radius of the circle is

At a particular instant velocity and acceleration of a particle are (-hat(i)+hat(j)+2hat(k))m//s and (3hat(i)-hat(j)+hat(k))m//s^(2) respectively at the given instant particle's speed is :

A constant force F is applied at the top of a ring as shown in figure. Mass of the ring is M and radius is R. Angular momentum of particle about point of contact at time t

A particle is moving in a circular path. The acceleration and momentum of the particle at a certain moment are a=(4 hat(i)+3hat(j))m//s^(2) and p=(8 hat(i)-6hat(j))"kg-m/s" . The motion of the particle is

A particle is moving in x-y plane. At an instant, it has velocity (4 hat (i) + 4 hat(j)) m//s and acceleration (3 hat(i) + 5 hat(j)) m//s^(2) At that instant, the radius of curvature of its path will be :