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A very broad elevator is going up vertic...

A very broad elevator is going up vertically with a constant acceleration of `2m//s^(2)`. At the instant when its velocity is `4m//s` a ball is projected form the floor of the lift with a speed of `4m//s` relative to the floor at an elevation of `30^(@)`. Time taken by the ball to return the floor is `(g=10ms^(2))`

A

`2 sqrt(3) m`

B

`sqrt(3) m`

C

`(2)/(sqrt(3)) m`

D

`2m`

Text Solution

AI Generated Solution

To solve the problem step by step, we will analyze the motion of the ball projected from the elevator. ### Step 1: Understand the situation The elevator is moving upward with a constant acceleration of \(2 \, \text{m/s}^2\) and has a velocity of \(4 \, \text{m/s}\) at the moment the ball is projected. The ball is projected at an angle of \(30^\circ\) with a speed of \(4 \, \text{m/s}\) relative to the elevator's floor. ### Step 2: Determine the effective acceleration of the ball The ball experiences two accelerations: 1. The gravitational acceleration \(g = 10 \, \text{m/s}^2\) acting downward. ...
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Knowledge Check

  • A girl standing on a stationary lift (open from above) throws a ball upwards with initial speed 50 m s^(-1) . The time taken by the ball to return to her hands is (Take g = 10 m s^(-2) )

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