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Calculate the heat of formation of metha...

Calculate the heat of formation of methane in `kcalmol^(-1)` using the following thermo chemical reactions
`C(s)+O_(2)toCO_(2)(g) , DeltaH=-94.2 kcal mol^(-1)`
`H_(2)(g)+1/2O_(2)(g)toH_(2)O(l) , DeltaH=-68.3 kcal mol^(-1)`
`CH_(4)(g)+2O_(2)(g)toCO_(2)(g)+2H_(2)O(l) , DeltaH=-210.8 kcal mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
`-20`
`C(s) + O_2 (g) to Ca_(2) (g) + 94.2 ` Kcal `" "….(1)`
`H_2 (g) + 1/2 O_2 (g) to H_2 O (l) + 68.3 kcal " "….(2)`
`CH_4 (g) + 2O_2 (g) to CO_2 (g) + 2H_2 (l) + 210.8 kcal " "….(3)`
The required equation is
`C(g) + 2H_2 (g) to CH_4 (g)`
so, `DeltaH_f = Delta H_l + (2xx DeltaH_2) - Delta H_3 =-20 "kcal mol"^(-1)`.
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