In the expansion of `(e^(x)-1-x)/(x^(2))` is ascending powers of x the fourth term is

Options

A. `(x^(3))/(5!)`
B. `(x^(4))/(4!)`
C. `(x^(3))/(3!)`
D. none of these

Explanation

To find the fourth term in the expansion of \(\frac{e^x - 1 - x}{x^2}\), we can follow these steps:

### Step 1: Expand \(e^x\)
We start with the Taylor series expansion of \(e^x\):
\[ e^x = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + \frac{x^4}{4!} + \cdots \]

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