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Let A be a matrix of rank r. Then,...

Let A be a matrix of rank r. Then,

A

`"rank " (A^T)=r`

B

`"rank "(A^T)ltr`

C

`"rank " (A^T)gtr`

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the rank of the transpose of a matrix \( A \) given that the rank of \( A \) is \( r \). ### Step-by-Step Solution: 1. **Understanding Rank**: The rank of a matrix is defined as the maximum number of linearly independent row vectors or column vectors in the matrix. If the rank of matrix \( A \) is \( r \), it means there are \( r \) linearly independent rows or columns in \( A \). **Hint**: Recall that the rank indicates the number of non-zero rows or columns in the matrix. 2. **Transpose of a Matrix**: The transpose of a matrix \( A \), denoted as \( A^T \), is formed by swapping the rows and columns of \( A \). Thus, if \( A \) has dimensions \( m \times n \), then \( A^T \) will have dimensions \( n \times m \). **Hint**: Remember that transposing a matrix does not change the linear independence of its rows or columns; it merely interchanges them. 3. **Rank of the Transpose**: It is a fundamental property of matrices that the rank of a matrix is equal to the rank of its transpose. Therefore, if the rank of \( A \) is \( r \), then the rank of \( A^T \) is also \( r \). **Hint**: Use the property that \( \text{rank}(A) = \text{rank}(A^T) \) to conclude the result. 4. **Conclusion**: Since we have established that the rank of \( A^T \) is equal to the rank of \( A \), we can conclude that the rank of \( A^T \) is also \( r \). **Hint**: Summarize your findings by stating that the rank remains unchanged under transposition. ### Final Answer: The rank of \( A^T \) is \( r \).
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Knowledge Check

  • Let A be a square matrix of order 3 times 3 , then abs(kA) is equal to

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    B
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    C
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