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If I(1) is the centre of the escribed ci...

If `I_(1)` is the centre of the escribed circle touching side BC of `!ABC` in which `angleA=60^(@)`, then `I_(1)` A =

A

`r_(1)`

B

`(r_(1))/2`

C

`2r_(1)`

D

none of these

Text Solution

AI Generated Solution

To solve the problem, we need to find the distance from the center of the escribed circle \( I_1 \) to vertex \( A \) of triangle \( ABC \), given that \( \angle A = 60^\circ \). ### Step-by-Step Solution: 1. **Understanding the Escribed Circle**: The escribed circle (or excircle) opposite to vertex \( A \) of triangle \( ABC \) has its center denoted as \( I_1 \). The radius of this circle is denoted as \( R_1 \). 2. **Using the Formula**: The distance from the center of the escribed circle \( I_1 \) to vertex \( A \) can be calculated using the formula: \[ ...
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