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The Cartesian product A xxA has 9 elemen...

The Cartesian product `A xxA` has 9 elements among which are found `(-1," "0)" "a n d" "(0," "1)` . Find the set A and the remaining elements of `A xxA` .

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To solve the problem, we need to find the set \( A \) and the remaining elements of the Cartesian product \( A \times A \). ### Step-by-Step Solution: 1. **Understanding the Cartesian Product**: The Cartesian product \( A \times A \) consists of all ordered pairs \( (a, b) \) where \( a \) and \( b \) are elements of set \( A \). The number of elements in \( A \times A \) is given by \( n(A) \times n(A) \), where \( n(A) \) is the number of elements in set \( A \). 2. **Given Information**: We know that \( A \times A \) has 9 elements. Therefore, we can set up the equation: \[ n(A) \times n(A) = 9 \] This implies: \[ n(A)^2 = 9 \] Taking the square root of both sides, we find: \[ n(A) = 3 \] 3. **Identifying Elements of Set \( A \)**: We are given two elements from the Cartesian product: \( (-1, 0) \) and \( (0, 1) \). Since these pairs are formed from the elements of set \( A \), we can conclude that the elements of \( A \) must include \( -1 \), \( 0 \), and \( 1 \). Thus, we can write: \[ A = \{-1, 0, 1\} \] 4. **Finding Remaining Elements of \( A \times A \)**: Now, we need to find all the elements of \( A \times A \). The Cartesian product will include all combinations of the elements in \( A \): - Pairing \( -1 \) with each element in \( A \): - \( (-1, -1) \) - \( (-1, 0) \) (given) - \( (-1, 1) \) - Pairing \( 0 \) with each element in \( A \): - \( (0, -1) \) - \( (0, 0) \) - \( (0, 1) \) (given) - Pairing \( 1 \) with each element in \( A \): - \( (1, -1) \) - \( (1, 0) \) - \( (1, 1) \) 5. **Listing All Elements**: Now, we can list all the elements of \( A \times A \): \[ A \times A = \{ (-1, -1), (-1, 0), (-1, 1), (0, -1), (0, 0), (0, 1), (1, -1), (1, 0), (1, 1) \} \] The given elements \( (-1, 0) \) and \( (0, 1) \) are already included in this list. ### Remaining Elements: The remaining elements of \( A \times A \) that were not given in the question are: - \( (-1, -1) \) - \( (-1, 1) \) - \( (0, -1) \) - \( (0, 0) \) - \( (1, -1) \) - \( (1, 0) \) - \( (1, 1) \) ### Final Answer: Set \( A = \{-1, 0, 1\} \) and the remaining elements of \( A \times A \) are: - \( (-1, -1) \) - \( (-1, 1) \) - \( (0, -1) \) - \( (0, 0) \) - \( (1, -1) \) - \( (1, 0) \) - \( (1, 1) \)

To solve the problem, we need to find the set \( A \) and the remaining elements of the Cartesian product \( A \times A \). ### Step-by-Step Solution: 1. **Understanding the Cartesian Product**: The Cartesian product \( A \times A \) consists of all ordered pairs \( (a, b) \) where \( a \) and \( b \) are elements of set \( A \). The number of elements in \( A \times A \) is given by \( n(A) \times n(A) \), where \( n(A) \) is the number of elements in set \( A \). 2. **Given Information**: ...
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