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The parametric point on the circle x^(2)...

The parametric point on the circle `x^(2)+y^(2)=a^(2)` is :

A

`(acostheta,asintheta)`

B

`(acostheta, bsintheta)`

C

`(bcostheta, asintheta)`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the parametric point on the circle defined by the equation \(x^2 + y^2 = a^2\), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Equation of the Circle**: The given equation is \(x^2 + y^2 = a^2\). This is the standard form of a circle centered at the origin \((0, 0)\) with radius \(a\). **Hint**: Recognize that the general form of a circle's equation is \(x^2 + y^2 = r^2\), where \(r\) is the radius. 2. **Compare with the Standard Form**: From the equation \(x^2 + y^2 = a^2\), we can see that the radius \(r\) is equal to \(a\). **Hint**: Identify the radius by comparing the given equation with the standard circle equation. 3. **Use Parametric Equations**: The parametric equations for a circle of radius \(r\) are given by: \[ x = r \cos \theta \] \[ y = r \sin \theta \] Since we have determined that \(r = a\), we can substitute \(a\) into these equations. **Hint**: Remember that the parametric equations for circles involve trigonometric functions. 4. **Substitute the Radius**: Substitute \(r = a\) into the parametric equations: \[ x = a \cos \theta \] \[ y = a \sin \theta \] **Hint**: Ensure that you replace \(r\) with the correct value from the previous step. 5. **Write the Parametric Point**: The parametric point on the circle can now be expressed as: \[ (x, y) = (a \cos \theta, a \sin \theta) \] **Hint**: Combine the results from the previous step to form the final parametric point. ### Final Answer: The parametric point on the circle \(x^2 + y^2 = a^2\) is given by: \[ (a \cos \theta, a \sin \theta) \]
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