Home
Class 11
MATHS
If a line is drawn through a fixed point...

If a line is drawn through a fixed point `P(alpha,beta)` to cut the circle `x^(2)+y^(2)=a^(2)` at A and B , then find the value of PA. PB

A

`(alpha-beta)^(2)+r^(2)`

B

`alpha^(2)+beta^(2)-r^(2)`

C

`(alpha+beta)^(2)+r^(2)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CONIC SECTION

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 11.1|15 Videos

  • CONIC SECTION

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 11.2|12 Videos

  • CONIC SECTION

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 11F|10 Videos

  • COMPLEX NUMBERS AND QUADRATIC EQUATION

    NAGEEN PRAKASHAN ENGLISH|Exercise MISCELLANEOUS EXERCISE|20 Videos

  • INTRODUCTION OF THREE DIMENSIONAL GEOMETRY

    NAGEEN PRAKASHAN ENGLISH|Exercise Miscellaneous Exercise|6 Videos

Similar Questions

Explore conceptually related problems

A line is drawn through a fix point P( alpha, beta ) to cut the circle x^2 + y^2 = r^2 at A and B. Then PA.PB is equal to :

A line is drawn through a fix point P( alpha, beta ) to cut the circle x^2 + y^2 = r^2 at A and B. Then PA.PB is equal to :

If a line is drawn through a point A(3,4) to cut the circle x^(2)+y^(2)=4 at P and Q then AP .AQ=

A line is drawn through the point P(3,11) to cut the circle x^(2)+y^(2)=9 at A and B. Then PA.PB is equal to

If a circle passes through the point (a, b) and cuts the circlex x^2+y^2=p^2 equation of the locus of its centre is

If a line passes through the point P(1,-2) and cuts the x^2+y^2-x-y= 0 at A and B , then the maximum of PA+PB is

If the line y-sqrt(3)x + 3=0 cuts the parabola y^2=x + 2 at A and B, then find the value of PA.PB(where P=(sqrt(3),0)

If a line through P(-2,3) meets the circle x^(2)+y^(2)-4x+2y+k=0 at A and B such that PA.PB=31 then the radius of the circles is

Through a fixed point (h,k) secants are drawn to the circle x^(2)+y^(2)=r^(2) . Show that the locus of the mid points of the position of the secants intercepted by the circle is x^(2)+y^(2)=hx+ky .

A line is drawn passing through point P(1,2) to cut positive coordinate axes at A and B . Find minimum area of DeltaPAB .

Home
Profile