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If two fair dices are thrown and digits ...

If two fair dices are thrown and digits on dices are a and b, then find the probability for which `omega^(ab) = 1`, (where `omega` is a cube root of unity).

Text Solution

Verified by Experts

The correct Answer is:
`(5)/(9)`

Total number of cases n(S) = 36
Since `omega^(ab)` = 1, ab must be multiple of 3.
So, at least one of a and b must be multiple of 3.
If none of the dices shows 3 or 6, number of cases is `4 xx 4 = 16`.
So, number of cases in which at least one of the dices shows 3 or 6 is 36 - 16 = 20.
`therefore` Required probability = `(20)/(36) = (5)/(9)`
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Knowledge Check

  • If two dice are thrown simultaneously, then the probability that the sum of the numbers which come up on the dice to be more than 5 is

    A
    `(5)/(36)`
    B
    `(1)/(6)`
    C
    `(5)/(18)`
    D
    `(13)/(18)`
  • Two dice are thrown simultaneously. Then the probability of getting two odd numbers is

    A
    `(1)/(6)`
    B
    `(2)/(6)`
    C
    `(7)/(36)`
    D
    `(1)/(4)`
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