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Tangents are drawn to `x^(2)+y^(2)=1` from any arbitrary point P on the line `2x+y-4=0`.Prove that corresponding chords of contact pass through a fixed point and find that point.

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Variable point on the line `2x+y-4` is `P(t,4-2t),t in R`.
Equation of chord of contact `x^(2)+y^(2)=1` w.r.t. point P is
`tx +(4-2t)y=1`
or `(4y-1)+t(x-2y)=0`
This is the equation of family of straight lines which are concurrent at point of intersection of lines `4y-1=0` and `x-2y=0`.
Therefore , line are concurrent at `Q (1//2,1//4)`
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