Home
Class 12
MATHS
If a circle whose center is (1,-3) touch...

If a circle whose center is `(1,-3)` touches the line `3x-4y-5=0` , then find its radius.

Text Solution

Verified by Experts

The correct Answer is:
2
Radius`=`Perpendicular distance form `(1,-3)` to `(3x-4y-5=0)=|(3+12-5)/(sqrt((5)^(2)))|=2`
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

2x+y=0 is the equation of a diameter of the circle which touches the lines 4x-3y+10=0 and 4x-3y-30=0. The centre and radius of the circle are

If a line passing through the origin touches the circle (x-4)^2+(y+5)^2=25 , then find its slope.

If 3x+y=0 is a tangent to a circle whose center is (2,-1) , then find the equation of the other tangent to the circle from the origin.

If one end of the diameter is (1, 1) and the other end lies on the line x+y=3 , then find the locus of the center of the circle.

Find the equation of the circle whose radius is 5a n d which touches the circle x^2+y^2-2x-4y-20=0 externally at the point (5,5)dot

The line 2x-y+1=0 is tangent to the circle at the point (2, 5) and the center of the circle lies on x-2y=4 . Then find the radius of the circle.

If a circle S(x, y)=0 touches at the point (2,3) of the line x+y=5 and S(1,2)=0 , then (sqrt2 xx Radius) of such circle is

A circle touches the x-axis and also thouches the circle with center (0, 3) and radius 2. The locus of the center of the circle is (a)a circle (b) an ellipse (c)a parabola (d) a hyperbola

Find the equation of the circle having radius 5 and which touches line 3x+4y-11=0 at point (1, 2).

Find the equation of a circle with center (4, 3) touching the circle x^2+y^2=1