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The distance covered by a particle movin...

The distance covered by a particle moving in a straight line from a fixed point on the line is `s ,` where `s^2=a t^2+2b t+c dot` Then prove that acceleration is proportional to `s^(-3)dot`

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Knowledge Check

  • If the velocity of a particle moving along a straight line is directly proportional to the square of its distance from a fixed point on the line . Then its acceleration is proportional to ………………….

    A
    s
    B
    `s^(2)`
    C
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    D
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  • The velocity v of a particle moving along a straight line when at a distance x from the origin is given by a + bv^(2) = x^(2) where a and b are constants then the acceleration is:

    A
    `(b)/(x)`
    B
    `(a)/(x)`
    C
    `(x)/(b)`
    D
    `(x)/(a)`

  • A particle moves in a straight line according to the relation: x = t ^ { 3 } - 4 t ^ { 2 } + 3 t Find the acceleration of the particle at displacement equal to zero.

    A
    (-8,-2,10)
    B
    (-1,-2,10)
    C
    (8,2,10)
    D
    (1,2,10)

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