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Compound A having molecular formula, C(4...

Compound A having molecular formula, `C_(4)H_(10)O` is found to be soluble in concentrated sulphuric acid. It does not react with sodium metal or potassium permanganate. On heating with excess of HI, it gives a single alkyl halide. Deduce the structure of compound A and explain all the reactions.

Text Solution

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(i) As compound A does not react with sodium metal or potassium permanganate, it cannot be an alcohol.
(ii) As compound A dissolves in conc. `H_(2)SO_(4)`, it may be an ether.
(iii) As compound A on heating with excess of HI gives a single alkyl halide, therefore compound a must be a symmetrical ether.
(iv) The only symmetrical ether molecular formula, `C_(4)H_(10)O` is diethy ether. Thus compound A is diethyl ether, `CH_(3)-CH_(2)-O-CH_(2)-CH_(3)CH_(3)CH_(2)-O-CH_(2)CH_(3)overset("Cone. "H_(2)SO_(4))(to)[underset("Soluble oxonium salt")(CH_(3)-CH_(2)-underset(H)underset(|)overset(+)(O)-CH_(2)-CH_(3))]HSO_(4)^(-)`
`underset("Diethyl ether")underset((A))(CH_(3)CH_(2)OCH_(2)CH_(3))underset(Delta)overset(HI)(to)underset("Ethyl iodide")(2CH_(3)CH_(2)-I)`
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Compound (A), C_(4)H_(10)O , is found to be soluble in sulphuric acid (A) does not react with metallic sodium or potassium permanganate solution When (A) is heated with excess of HI, it is converted to a single alkyl halide. What is the structural formula of (A) ?

A compound A of molecular formula C_(3)H_(7)O_(2)N on reaction with iron and concentrated HCl gives a compound B of molecular formula C_(3)H_(9)N . Compound B on treatment with NaNO_(2) and HCl gives another compound C of molecular formula C_(3)H_(8)O . Compound C gives effervescence with sodium. On oxidation with CrO_(3) , compound C gives a saturated aldehyde containing three carbon atoms. Deduce the structures of compounds A, B and C and write the equations of the reactions involved.

Knowledge Check

  • The compound having molecular formula C_4H_10O can show:

    A
    Metamerism
    B
    Functional isomerism
    C
    Positional isomerism
    D
    All of the above
  • An organic compound A reacts with sodium metal and forms B. On heating with conc. H_2SO_4,A gives diethyl ether. So A and B are:

    A
    `C_3H_7OH and CH_3ONa`
    B
    `CH_3OH and CH_3ONa`
    C
    `C_4H_9OH and C_4H_9ONa`
    D
    `C_2H_5OH and C_2H_5ONa`
  • An organic compound A reacts with sodium metal and forms B. On heating with conc. H_2SO_4,A gives diethyl ether. So A and B are:

    A
    `C_3H_7OH and CH_3ONa`
    B
    `CH_3OH and CH_3ONa`
    C
    `C_4H_9OH and C_4H_9ONa`
    D
    `C_2H_5OH and C_2H_5ONa`
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