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Write the mechanism of the reaction of H...

Write the mechanism of the reaction of HI with methoxy methane.

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With equimolar amounts of HI and methoxy methane, a mixture of methyl alcohol and methyl iodide is obtained
The mechanism is as follows :

Step III If however, excess of HI is used, methyl alcohol formed in step II is also coverted into methyl iodide. It can be explained by the following mechanism :
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