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The potential energy of a force filed ve...

The potential energy of a force filed `vec(F)` is given by `U(x,y)=sin(x+y)`. The force acting on the particle of mass m at `(0,(pi)/4)` is

A

1

B

`sqrt2`

C

`(1)/(sqrt2)`

D

0

Text Solution

Verified by Experts

The correct Answer is:
A
`(dU)/(dx)=cos(x+y)`,
`(dU)/(dy)=cos(x+y)`
`vecF=-cos(x+y)hati-cos(x+y)hatj`
`=-cos(0+pi/4)hati-cos(0+pi/4)hatj`
`|vecF|=1`
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