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In a guitar , two strings A and b made o...

In a guitar , two strings A and b made of same material are slightly out of tune and produce beats of frequency 6 Hz. when tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency od A is 530 hz, the original frequency of B will be

A

524 Hz

B

536 Hz

C

537 Hz

D

523 Hz

Text Solution

Verified by Experts

The correct Answer is:
A
Difference of frequency of A and B is 6Hz
`F_A - F_B = 6Hz`
Frequency of B when tension decrease be `F._B`.
`F_A - F._B = 7Hz`
So `F_A gt F_B`
`F_A - F._B = 6Hz`
`F_A = 530 Hz`
`F_B = 524 Hz`
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