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An electron falls from rest through a ve...

An electron falls from rest through a vertical distance h in a uniform and vertically upwards directed electric field E. The direction of electric field is now reversed , keeping its magnitude the same. A proton is allowed to fall from rest in it through the same vertical distance h. The time of fall of the electron, in comparison to the time of fall proton is

A

10 times greater

B

5 times greater

C

Smaller

D

Equal

Text Solution

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The correct Answer is:
B
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An electron (mass m_(e ) )falls through a distance d in a uniform electric field of magnitude E. , The direction of the field is reversed keeping its magnitudes unchanged, and a proton(mass m_(p) ) falls through the same distance. If the times taken by the electrons and the protons to fall the distance d is t_("electron") and t_("proton") respectively, then the ratio t_("electron")//t_("proton") .

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Knowledge Check

  • An electron falls from rest through a vertical distance h in a uniform and vertically upward directed electric field E. the direction of electric field is now reversed, keeping its magnitude the same. A proton is allowed to fall from rest in it through the same vertical distance h.The time of fall of the electron, in comparison to the time of flal of the proton is

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    10 times greater
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    D
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  • An electron falls through a small distance in a uniform electric field of magnitude 2xx10^(4)NC^(-1) . The direction of the field reversed keeping the magnitude unchanged and a proton falls through the same distance. The time of fall will be

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