A toy car with charge `q` moves on a frictionless horizontal plane surface under the influence of a uniform electric field `vec E`. Due to the force `q vec E`, its velocity increases from `0` to `6 m//s` in one second duration. At that instant the direction of field is reversed.
The car continues to move for two more seconds under the influence of this field. The average velocity and the average speed of the toy car between `0` to `3` seconds are respectively.

Options

A. `1` m/s, `3.5` m/s
B. `1` m/s, `3` m/s
C. `2` m/s, `4` m/s
D. `1*5` m/s, `3` m/s

Answer

B

Explanation

Between `t=0` to `t=1` s
`v=u+atimplies 6=0+axx1`
`a=6"m/s"^(2)`
`"Average speed"=("Total distance")/("Total time")`
`=(3X)/(3)=X` m/s
where `X=0+(1)/(2)xx6xx(1)^(2)=3` m
`:.` Average speed = `3` m/s
`"Average velocity"=("Total distance")/("Total time")`
`=(X)/(3)=(3)/(3)=1` m/s