Two plane mirrors are inclined at 70^@. ...

Two plane mirrors are inclined at `70^@`. A ray incident on one mirror at incidence angle `theta` after reflection falls on the second mirror and is reflected from there parallel to the first mirror, The value of `theta` is

`50^@`

`45^@`

`30^@`

`55^@`

Text Solution

Verified by Experts

The correct Answer is:

From `Delta ` law
`x = 180^@ - (90^@ - q) - 70^@`
`implies x = 20 + q`
According to the question : AB is parallel to `r_c = 70^@`
also due to reflection `x = y implies 20 + q = 70^@`
`implies q = 50^@`

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Two plane mirrors are inclined at 70^(@) A ray incident on one mirror at angle theta . After reflection, falls on the second mirror and is reflected from there parallel to the first mirror theta is

`50^(@)`

`45^(@)`

`30^(@)`

`55^(@)`

Two plane mirrors are inclined at an angle theta to one another A ray of light incident on the first mirror and parallel ot the second mirror is reflected from the second mirror parallel to the first mirror , What is the value of theta

`0^(@)`

`45^(@)`

`60^(@)`

`90^(@)`

Two plane mirrors are inclined at an angle theta to one another. A ray of light incident on the first mirror and parallel to the second mirror is reflected from the second mirror parallel to the first mirror. What is the value of theta ?

a `0^(@)`

( b) `45^(@)`

c `60^(@)`

d `90^(@)`