For a doubly ionised Li-atom...

For a doubly ionised Li-atom

Angular momentum of an electron in `3rd` orbit is `(3h)/(2pi)`

energy of electron in `2nd` ecited state is `-13.6 eV`.

Speed of electron in `3rd` orbit is `(c)/(137)`, where c is speed of light

Kinetic energy of electron is 2nd excited state is half of the magnitude of the potential energy.

Verified by Experts

The correct Answer is:

A, B, C, D

(A) `L = (nh)/(2pi)` , (B) `E = (-13.6Z^(2))/(n^(2))`
(C ) `v = (c )/(137)(Z)/(n)` , (D) `K = -(U)/(2)`

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Hydrogen (""_(1)H^(1)) , Deuterium (""_(1)H^(2)) , single ionised Helium (""_(2)He^(4))^(+) and doubly ionised lithium (""_(3)Li^(6))^(++) all have one electron around the nucleus. Consider an electron transition from n=2 to n=1. If the wavelength of emitted radiation are lamda_(1),lamda_(2),lamda_(3) and lamda_(4) respectively then approximately which one of the following is corrent ?

`lamda_(1)=lamda_(2)=2lamda_(3)=lamda_(4)`

`lamda_(1)=lamda_(2)=4lamda_(3)=9lamda_(4)`

`lamda_(1)=2lamda_(2)=3lamda_(3)=4lambda_(4)`

`4lamda_(1)=2lamda_(2)=2lamda_(3)=lamda_(4)`

13.6 eV

27.2 eV

6.8 eV

54.4 eV

`Li lt B lt Be lt C " and " Na lt Al lt Mg lt Si`

`Li lt Be lt B lt C " and " Na lt Mg lt Al lt Si`

`C lt Be lt B lt Li " and " Si lt Mg lt Al lt Na`

None of these