The photon radiated from hydrogen corresponding to `2^(nd)` of Lyman series is abosorbed by a hydrogen like atom `'X'` in `2^(nd)` excited state. As a result the hydrogen like atom `'X'` makes a transition to `n^(th)` orbit. Then :

Options

A. `X = He^(+), n = 4`
B. `X = Li^(++), n = 6`
C. `X = He^(+), n = 6`
D. `X = Li^(++), n = +9`

Answer

D

Explanation

`13.6[1/1 - 1/9] = 13.6Z^(2)(1/9 - 1/(n^(2)))`