The photon radiated from hydrogen corres...

The photon radiated from hydrogen corresponding to `2^(nd)` of Lyman series is abosorbed by a hydrogen like atom `'X'` in `2^(nd)` excited state. As a result the hydrogen like atom `'X'` makes a transition to `n^(th)` orbit. Then :

`X = He^(+), n = 4`

`X = Li^(++), n = 6`

`X = He^(+), n = 6`

`X = Li^(++), n = +9`

Verified by Experts

The correct Answer is:

`13.6[1/1 - 1/9] = 13.6Z^(2)(1/9 - 1/(n^(2)))`

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As an electron makes a transition from an excited state to the ground state of a hydrogen like atom/ion.

its kinetic energy increases but potential and total energy decreases

kinetic energy, potential energy and total energy decrease.

kinetic energy decreases, potential energy increases but total energy remain same.

kinetic energy and total energy decreases but potential energy increases.

`16:1`

`2:1`

`4:1`

`8:1`

3.4

12.09

10.2

13.6