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A satellite of mass m revolves in a circ...

A satellite of mass m revolves in a circular orbit of radius R a round a planet of mass M. Its total energy E is :-

A

`- (GMm)/(2R)`

B

`+ (GMm)/(3R)`

C

`- (GMm)/R`

D

`+ (GMm)/R`

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The correct Answer is:
A
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Knowledge Check

  • A satellite of mass m revolving in a circular orbit of radius 3 R_E around the earth (mass of earth is Me and radius is R_E ). How much excess energy be spent to bring it to orbit of radius 9 R_E ?

    A
    `(GM_Em)/(3R_E)`
    B
    `(GM_Em)/(18R_E)`
    C
    `(3GM_Em)/(2R_E)`
    D
    `(GM_Em)/(9R_E)`

  • A satellite of mass m revolves around the earth of radius R at a height x from its surface. If g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is .........

    A
    gx
    B
    `(gR)/(R-x)`
    C
    `(gR^2)/(R+x)`
    D
    `((gR^2)/(R+x))^(1/2)`

  • These both situation is truely shown in graph (D) A satellite of mass m is orbiting the earth (of radius R) at a height h from its surface. The total energy of the satellite in terms of g_0 , the value of acceleration due to gravity at the earth's surface, is

    A
    `(2mg_0R^2)/(R+h)`
    B
    `-(2mg_0R^2)/(R+h)`
    C
    `(mg_0R^2)/(2(R+h))`
    D
    `-(mg_0R^2)/(2(R+h))`

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