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The mean radius of the earth's orbit rou...

The mean radius of the earth's orbit round the sun is `1.5xx10^(11)` . The mean radius of the orbit of mercury round the sun is `6xx10^(10)m`. The mercury will rotate around the sun in

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The correct Answer is:
`(2/5)^(3//2)` years
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The radius of the innermost electron orbit of a hydrogen atom is 5.3 xx 10^(–11) m . What are the radii of the n = 2 and n =3 orbits?

The radius of the innermost electron orbit of a hydrogen atom is 5.3 xx 10^(-11)m . What are the radii of the n = 2 and n = 3 orbits ?

Knowledge Check

  • The radius of the innermost electron orbit of a hydrogen atom is 5.3xx10^(-11) m. What are the radii of the n = 2 and n = 3 orbits?

    A
    `R_(2)=2.12xx10^(-11)m,R_(3)=4.77Å`
    B
    `R_(2)=2.12xx10^(-10)m,R_(3)=4.77Åxx10^(-11)m`
    C
    `R_(2)=2.12Å,R_(3)=4.77Å`
    D
    `R_(2)=2.12xx10^(10)Å,R_(3)=4.77xx10^(-10)Å`

  • The radius of hydrogen atom in its ground state is 5.3xx10^(-11) m. After collision with an electron it is found to have a radius 21.2xx10^(-11) m, then principle quantum number n of the final state of the atom ......

    A
    n=4
    B
    n=2
    C
    n=16
    D
    n=3

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    How will you 'weigh the sun', that is estimate its mass ? The mean orbital radius of the earth around the sun is 1.5 xx 10^(8) km.

    How will you ‘weigh the sun’, that is estimate its mass? The mean orbital radius of the earth around the sun is 1.5 xx 10^(8) km.

    If earth describes an orbit round the sun of double its present radius, what will be the year on earth ?

    The mas of the earth is 6 xx 10^(24)kg and that of the moon is 7.4 xx 10^(24)kg . If the distance between the centres of the earth and the moon is 3.84 xx 10^(5)km , calculate the force exerted by the earth of the moon. G=6.7 xx 10^(-11)Nm^(2) kg^(-2) .

    In the Rutherford’s nuclear model of the atom, the nucleus (radius about 10^(–15) m) is analogous to the sun about which the electron move in orbit (radius ~~ 10^(–10) m) like the earth orbits around the sun. If the dimensions of the solar system had the same proportions as those of the atom, would the earth be closer to or farther away from the sun than actually it is? The radius of earth’s orbit is about 1.5 xx 10^(11) m. The radius of sun is taken as 7 xx 10^8 m .

    The principle of 'parallax' in section 2.3.1 is used in the determination of distances of very distant starts. The baseline AB is the line joining the Earth's two locations six months apart in its orbit around the Sun. That is, the baseline is about the diameter of the Earth's orbit = 3xx10^(11)m . However, even the nearest stars are so distant that with such a long baseline, they show parallax only of the order of 1" (second) of arc or so. A parsec is a conventent unit of length on the astronomical scale. It is the distance of an object that will show a parallax of 1" (second of arc) from opposite ends of a baseline equal to the distance from the Earth to the Sun. How much is a parsec in terms of metres ?

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