Home
Class 8
PHYSICS
The object or image distance is taken as...

The object or image distance is taken as positive

A

if the length is measured opposite to the direction of the incident ray.

B

if the length is measured in the direction of the incident ray.

C

if the length is measured opposite to the direction of the refracted ray.

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the sign convention for object and image distances in optics, we need to analyze the options provided based on the behavior of light rays. Here’s a step-by-step breakdown of the solution: ### Step-by-Step Solution: 1. **Understanding the Sign Convention**: - In optics, the sign convention is crucial for determining whether the distances are positive or negative. The direction of the incident ray is the key factor in this convention. 2. **Identify the Direction of the Incident Ray**: - The incident ray is the ray that approaches the mirror or lens. We need to establish which direction this ray is coming from to determine our positive and negative distances. 3. **Positive Distance**: - According to the sign convention, the distance is considered positive if it is measured in the same direction as the incident ray. This means that if you measure a distance in the direction the ray is coming from, it will be positive. 4. **Negative Distance**: - Conversely, if the distance is measured opposite to the direction of the incident ray, it will be considered negative. Therefore, if you measure in the opposite direction of where the incident ray is coming from, that distance is negative. 5. **Analyzing the Options**: - **Option 1**: "The object or image distance is taken as positive if the length is measured opposite to the direction of the incident ray." - This is incorrect because distances measured opposite to the incident ray are negative. - **Option 2**: "The object or image distance is taken as positive if the length is measured in the direction of the incident ray." - This is correct because distances measured in the direction of the incident ray are positive. - **Option 3**: "The object or image distance is taken as positive if the length is measured opposite to the direction of the reflected ray." - This is incorrect because the sign convention is based on the incident ray, not the reflected ray. - **Option 4**: "None of them." - This is incorrect because we have already established that Option 2 is correct. 6. **Conclusion**: - The correct answer is **Option 2**: "The object or image distance is taken as positive if the length is measured in the direction of the incident ray."
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • LIGHT

    PEARSON IIT JEE FOUNDATION|Exercise Concept Application (Level 2)|20 Videos
  • LIGHT

    PEARSON IIT JEE FOUNDATION|Exercise Concept Application (Level 3)|15 Videos
  • LIGHT

    PEARSON IIT JEE FOUNDATION|Exercise Concept Application (Level 1) Matching |1 Videos
  • KINEMATICS

    PEARSON IIT JEE FOUNDATION|Exercise CONCEPT APPLICATION (Level 3) (Application Based Questions ) |5 Videos
  • MAGNETISM

    PEARSON IIT JEE FOUNDATION|Exercise CONCEPT APPLICATION (Level 3)|4 Videos

Similar Questions

Explore conceptually related problems

The distance between an object and a screen is 100 cm. A lens can produce real image of the object on the screen for two different position between the screen and the object. The distance between these two positions is 40 cm. If the power of the lens is close to ((N)/(100))D where N is integer, the value of N is ___________.

An object of height 4 cm in front of a concave lens of focal length 20 cm . If the object distance is 30 cm, find the position and the height of the image.

Knowledge Check

  • The heights of objects or images are taken as negative when they are measured

    A
    downwards, perpendicular to the principal axis.
    B
    along the direction of incident rays.
    C
    upwards, perpendicular to the principal axis.
    D
    None of these
  • The image formed by a convex mirror of focal length 30 cm is a quarter of the object. The object distance and image distance, along with the sign convention, are tabulated below. Select the row containing the correct values of object and image distance:

    A
    `{:("Object Distance","Image Distance (v)"),("-90 cm","22.5 cm"):}`
    B
    `{:("Object Distance","Image Distance (v)"),("-22.5 cm ","+90 cm"):}`
    C
    `{:("Object Distance","Image Distance (v)"),("-90 cm","-22.5 cm"):}`
    D
    `{:("Object Distance","Image Distance (v)"),("-90 cm ","+90 cm "):}`
  • The sum of the reciprocals of object distance and image distance is equal to the ___________ of a mirror.

    A
    focal length
    B
    reciprocal of the focal length
    C
    radius of curvature
    D
    reciprocal of the radius of curvature
  • Similar Questions

    Explore conceptually related problems

    An object of height 4 cm is placed in front of a concave lens of focal length 40 cm. If the object distance is 60 cm, find the position and height of the image.

    An object of height 1 cm is placed in front of a concave lens of focal length 40cm . If the object distance is 60 cm , find the position and height of the image .

    An object of height 2 cm is kept in front of a concave lens of focal length 20 cm. If the object distance is 30 cm, find the position and the height of the image.

    The height of the real image in a convex lens is taken to be positive.

    The table below shows object and image distances for four objects placed in front of mirrors. For which one is the image formed by a convex spherical mirror? [Positive and negative signs are used in accordance with standard sign convention]