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The solution of the primitive integral e...

The solution of the primitive integral equation `(x^2+y^2)dy=x ydx` is `y=y(x)dot` If `y(1)=1` and `y(x_0)=e ,` then `x_0` is

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Knowledge Check

  • The solution of the differential equation y dx+(x+x^(2)y)dy=0 is -

    A
    `(1)/(xy)+log|y|=c`
    B
    `-(1)/(xy)+log|y|=c`
    C
    `(1)/(xy)+2log|y|=c`
    D
    `log|y|=cx`

  • The general solution of the differential equation (y dx - x dy)/(y ) = 0 is

    A
    `xy = C`
    B
    `x = Cy^(2)`
    C
    `y = Cx`
    D
    `y = Cx^(2)`

  • The solution of the equation (dy)/(dx)+y=e^(-x), y(0)=0 is -

    A
    `y=e^(-x)(x-1)`
    B
    `y=x e^(x)`
    C
    `y=xe^(-x)+1`
    D
    `y=x e^(-x)`

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