If the distance between the plane ax 2y + z = d and the plane containing the lines
`(x-1)/2=(y-2)/3=(z-3)/4` and `(x-2)/3=(y-3)/4=(z-4)/5`
is `sqrt6` , then value of |d| is
Text Solution
Verified by Experts
The correct Answer is:
`6`
Let normal to plane be `lhati+mhatj+nhatk` `" "2l+3m+4n=0` and `" "3l+4m+5n =0` `" "(l)/(-1) = (m)/(2)= (n)/(-1)` Equation of plane will be `" "a(x-1)+b (y-2)+c(z-3)=0` or `" "-1(x-1)+2(y-2)-1(z-3)=0` or `" "-x+1+2y-4-z+3=0` or `" "-x+2y+z=0` or `" "x-2y+z=0` or `" "(|d|)/(sqrt6) = sqrt6` or `" "d=6`
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