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In the figure shown here, a circle touch...

In the figure shown here, a circle touches the side BC of a triangle ABC at P and AB and AC produced at Q and R respectively. What is AQ equal to ?

A

One-third of the perimeter of `Delta` ABC.

B

Half of the perimeter of `Delta` ABC.

C

Two-third of the perimeter of `Delta` ABC

D

Three-fourth of the perimeter of `Delta` ABC

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • A circle touches the side BC of a Delta ABC at P and also touches AB and AC produced at Q and R, respectively. If the perimeter of Delta ABC = 26.4 cm, then the length of AQ is:

    A
    `8.8` cm
    B
    `13.2` cm
    C
    `15.4` cm
    D
    `17.6` cm

  • A circle touches the side BC of DeltaABC at D and AB and aC are produced to E and F, respectively. If AB=10cm, AC=8.6 cm and BC=6.4 cm then BE=?

    A
    `3.5cm`
    B
    `3.2cm`
    C
    `2.5cm`
    D
    `2.2cm`

  • The in circle of Delta ABC touches the sides BC, CA and AB at D, E and F respectively. Then AF + BD + CE is equal to :

    A
    `(1)/(2)` (Perimeter of `Delta` ABC)
    B
    `(1)/(3)` (Perimeter of `Delta` ABC)
    C
    `(1)/(4)` (Perimeter of `Delta` ABC)
    D
    Perimeter of `Delta` ABC

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    A circle is touching the side BC of Delta ABC at P and touching AB and AC produced at Q and R respectively Prove that AQ=(1)/(2) (Perimeter of Delta ABC)

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