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The distance between the points (a, b) a...

The distance between the points (a, b) and (-a, -b)

A

0

B

1

C

`sqrt(ab)`

D

`2sqrt(a^(2) + b^(2))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the distance between the points (a, b) and (-a, -b), we can use the distance formula in coordinate geometry. The distance formula between two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] ### Step-by-step Solution: 1. **Identify the Points**: - Let point P be \( (a, b) \) and point Q be \( (-a, -b) \). 2. **Substitute the Coordinates into the Distance Formula**: - Here, \( x_1 = a \), \( y_1 = b \), \( x_2 = -a \), and \( y_2 = -b \). - Substitute these values into the distance formula: \[ d = \sqrt{((-a) - a)^2 + ((-b) - b)^2} \] 3. **Simplify the Expressions**: - Calculate \( (-a) - a = -2a \) and \( (-b) - b = -2b \). - Now, substitute these back into the formula: \[ d = \sqrt{(-2a)^2 + (-2b)^2} \] 4. **Calculate the Squares**: - \( (-2a)^2 = 4a^2 \) and \( (-2b)^2 = 4b^2 \). - Therefore, we have: \[ d = \sqrt{4a^2 + 4b^2} \] 5. **Factor Out the Common Terms**: - Factor out 4 from the square root: \[ d = \sqrt{4(a^2 + b^2)} \] 6. **Simplify the Square Root**: - Since \( \sqrt{4} = 2 \), we can simplify further: \[ d = 2\sqrt{a^2 + b^2} \] ### Final Answer: The distance between the points \( (a, b) \) and \( (-a, -b) \) is \( 2\sqrt{a^2 + b^2} \). ---
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