1.0 g of a monpbasic acid when completely acted upon Mg gave 1.301 g of anhydrous Mg salt. Equivalent weight of acid is

Options

A. 35.54
B. 36.54
C. 17.77
D. 18.27

Answer

B

Explanation

`("Ew of acid")/("Ew of salt of Mg")=("Weight of acid")/("Weight of salt")`
`Mg+2HCl"(monobasic acid")rarrMgCl_(2)+H_(2)`
Let Ew of acid = Ew of H + Ew of acid radical
`therefore` Ew of salt of Mg = Ew of Mg + Ew of acid radical
`therefore("Ew of acid")/("Ew of Mg salt")=("Weight of acid")/("Weight of Mg salt")`
`rArr("Ew of H + Ew of acid radical (E)")/("Ew of Mg + Ew of acid radical (E)")=1.0/(1.301)`
`rArr(1+E)/(12+E)=1.0/(1.301)`
`thereforeE=35.54`
`therefore` Ew of acid = Ew of H + Ew of acid radical
`=1+35.54=36.54`